LngLatDirection.java 2.05 KB
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package cn.wisenergy.common.utils;

/**
 * @Author zyj
 * @Date 2020/5/6 18:18
 * @Description 计算一个经纬度在另一个经纬度什么方向
 */

public class LngLatDirection {

	public static void main(String[] args) {
		LngLatDirection lngLatDirection = new LngLatDirection();
		String str = getDirection(39.915322, 116.404341, 39.954713, 116.45982);
		System.out.println(str);
	}

	/**
	 * @param lat1 纬度1
	 * @param lng1 经度1
	 * @param lat2 纬度2
	 * @param lng2 经度2
	 * @return 方向
	 */
	public static String getDirection(double lat1, double lng1, double lat2, double lng2) {
		double jiaodu = getAngle(lat1, lng1, lat2, lng2);
		if ((jiaodu <= 10) || (jiaodu > 350))
			return "东";
		if ((jiaodu > 10) && (jiaodu <= 80))
			return "东北";
		if ((jiaodu > 80) && (jiaodu <= 100))
			return "北";
		if ((jiaodu > 100) && (jiaodu <= 170))
			return "西北";
		if ((jiaodu > 170) && (jiaodu <= 190))
			return "西";
		if ((jiaodu > 190) && (jiaodu <= 260))
			return "西南";
		if ((jiaodu > 260) && (jiaodu <= 280))
			return "南";
		if ((jiaodu > 280) && (jiaodu <= 350))
			return "东南";
		return "";
	}

	private static double getAngle(double lat1, double lng1, double lat2, double lng2) {
		double x1 = lng1;
		double y1 = lat1;
		double x2 = lng2;
		double y2 = lat2;
		double pi = Math.PI;
		double w1 = y1 / 180 * pi;
		double j1 = x1 / 180 * pi;
		double w2 = y2 / 180 * pi;
		double j2 = x2 / 180 * pi;
		double ret;
		if (j1 == j2) {
			if (w1 > w2)
				return 270; // 北半球的情况,南半球忽略
			else if (w1 < w2)
				return 90;
			else
				return -1;// 位置完全相同
		}
		ret = 4 * Math.pow(Math.sin((w1 - w2) / 2), 2) - Math.pow(
				Math.sin((j1 - j2) / 2) * (Math.cos(w1) - Math.cos(w2)), 2);
		ret = Math.sqrt(ret);
		double temp = (Math.sin(Math.abs(j1 - j2) / 2) * (Math.cos(w1) + Math
				.cos(w2)));
		ret = ret / temp;
		ret = Math.atan(ret) / pi * 180;
		if (j1 > j2) { // 1为参考点坐标
			if (w1 > w2)
				ret += 180;
			else
				ret = 180 - ret;
		} else if (w1 > w2)
			ret = 360 - ret;
		return ret;
	}
}