select case when `type`= 1 then '商机' when `type`= 0 then '项目' end AS type,dept_id, project_id,MIN(work_day) AS firstTime,MAX(work_day) AS lastTime,SUM(work_time)/8 AS totalTime,(SUM(work_time))/8*10 AS cost
select CASE WHEN t.type= 1 THEN "项目" WHEN t.type= 2 THEN "商机" END AS type,t.dept_id, t.project_id,MIN(t.work_day) AS firstTime,MAX(t.work_day) AS lastTime,SUM(t.work_time)/8 AS totalTime,(SUM(t.work_time))/8*10 AS cost,dept_name AS deptName,project_name AS projectName
from <includerefid="table"/>
from work_time_order t JOIN work_dept d ON t.dept_id=d.id
where status in (2,5) and project_id in
JOIN work_project p ON t.project_id=p.id
where status IN (2,5) AND t.type IN (1,2) AND project_id IN